24th IMO 1983 shortlist

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Problem 7

Let N be a positive integer. Define the sequence a0, a1, a2, ... by a0 = 0, an+1 = N(an + 1) + (N + 1)an + 2( N(N+1)an(an+1) )1/2. Show that all terms are positive integers.

 

Solution

Solution by Demetres Christofides

Induction on n. Note first that √an+1 = (√(N+1) √an + √N √(an+1) and √(an+1+1) = √N √an + √(N+1) √(an+1). So √N √(N+1) √an+1 √(an+1+1) = N(N+1)(an+an+1) + (2N+1) √N √(N+1) √an √(an+1) (*).

If an and an+1 are integers it follows from the definition that √N √(N+1) √an √(an+1) is an integer, and hence (*) implies that √N √(N+1) √an+1 √(an+1+1) is an integer. Hence an+2 is an integer. But it is easy to check that a0 = 0 and a1 = N are integers, so an is an integer for all n.

 


 

24th IMO shortlist 1983

© John Scholes
jscholes@kalva.demon.co.uk
26 Nov 2003
Last corrected/updated 26 Nov 03